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Comments on How to create a quotation containing the given token in a syntax word in Factor programming language
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How to create a quotation containing the given token in a syntax word in Factor programming language
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I am trying to define a syntax word as follows:
USING: kernel syntax parser fry prettyprint ;
IN: syn-try
SYNTAX: syn scan-word '[ _ ] . ;
Given a word, I want to create a quotation containing the word.
In the factor listener, if i do syn word I get [ \ word ]. How do I remove the \?
Language version is Factor 0.98 for Linux.
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Things must have changed, on .99 I get
syn this
[ "this" ]
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