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Comments on What might happen if I ignore warning?
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What might happen if I ignore warning?
#include <iostream>
using namespace std;
int linearSearch(int array[], int n, int key){
for(int i=0;i<=n;i++){
if(array[i]==key){
return i;
}
}
}
int main() {
int balance[] = {10,240,120,150,100};
cout<<linearSearch(balance, sizeof(balance)/sizeof(balance[0]), 150);
return 0;
}
When executing the code I got an warning. Should I really care of warning? I got expected output. Although, I was thinking of warning. What might happen if I ignore warning?
test.cpp: In function ‘int linearSearch(int*, int, int)’:
test.cpp:10:1: warning: control reaches end of non-void function [-Wreturn-type]
10 | }
| ^
When I add return 0; at end of for loop I don't get the error anymore. The warning was saying that the linearSearch method (function) wasn't returning always. But, can warning crash my applications?
Replying to last edit of Alexei : My question was about any type of warning not only above one. Above one was just an example. Anyway, I got more accurate answer in the thread
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