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Comments on How to use grep to print only specific word from a string
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How to use grep to print only specific word from a string
I have a variable that contains a string:
$CCSR = "branches/features/arm_and_musl"
I want to get only the part after the last /. In this case it's "arm_and_musl" but it can be anything.
So something like:
def dirname= sh " echo $CCSR | grep ????? "
But the main issue is that it can be anything. It is "branches/features" this time, though it will always be in this format, with only two forward slashes.
I'm not sure what to put here so that only the part I want is passed to the variable.
Could you please suggest any solutions for this?
Post
grep is not the right tool for your case. You can use basename:
basename a/b/c --> c
basename a/b/c/ --> c
or, in your case
basename branches/features/arm_and_musl --> arm_and_musl
which, within a sh script, you would use as
dirname=`basename "$CCSR"`
Note, that if you need to call sh explicitly, you have to give the -c command line argument to sh if you want to pass commands on the command line.
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